The radius of hydration for a body of mass 10 kg and MI about an axis of rotation `0.40` km `m^2` will be

If the radius of gyration of a solid disc of mass 10 kg about an axis is 0.40 m, then the moment of inertia of the disc about that axis is

Find the moment of inertia of a mass of 5 kg and another mass 10 kg about an axis of rotation which is 0.2 m from the 5 kg mass and 0.4 m from the 10 kg mass. Find the radius of gyration for the system.

Find MI of a triangular lamina of mass M about the axis of rotation AB shown in Fig.

Find MI of a triangular lamina of mass M about the axis of rotation AB shown in Fig.

Radius of gyration of a disc of mass 5kg, about a transverse axis passing through its centre is 14.14 cm. Find radius of gyration about its diameter and, hence, calculate M.I. about the diameter

The M.I. of a thin ring of mass M and radius R about an axis through the diameter in its plane will be:

The M.I. of a thin ring of mass M and radius R about an axis through the diameter in its plane will be:

Calculate the moment of inertia of a solid sphere of mass 10 kg and radius 0.5 m, rotating about an axis 0.2 m from the centre of the sphere .