Separation between the plates of a parallel plate capacitor is `d` and the area of each plates is `A`. When a slab of material of dielectric constant `k` and thickness `t(t lt d)` is introduced between the plates. Its capacitance becomes

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

A battery charges a parallel plate capacitor of thickness (d) so that an energy [U_(0)] is stored in the system. A slab of dielectric constant (K) and thickness (d) is then introduced between the plates of the capacitor. The new energy of the system is given by

A battery charges a parallel plate capacitor of thickness (d) so that an energy [U_(0)] is stored in the system. A slab of dielectric constant (K) and thickness (d) is then introduced between the plates of the capacitor. The new energy of the system is given by

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance.

A parallel plate capacitor has a capacitance of 100muF . The plates are at a distance d apart. A slab of thickness t(t = d) and dielectric constant 5 is introduced between the parallel plates. Then capacitance can be,

A parallel plate capacitor has a capacitance of 60 PF, when the plates of the capacitor and separated by a distance d. if a metal plate of thickness t=(d)/(3) is introduced between the plates, the capacitance will be