" 12."quad " Given "/_ABC sim Delta PQR," if "(AB)/(PQ)=(1)/(3)," then "(ar(/_ABC))/(ar(Delta PQR))=

Given /_ABC=/_PQR if (AB)/(PQ)=(1)/(3) then find (ar/_ABC)/(ar/_PQR)

Given triangle ABC ~ triangle PQR if (AB)/(PQ)=1/3 then find (ar triangle ABC)/(ar triangle PQR)

It is given that Delta ABC~Delta PRQ and (BC)/(QR)=(2)/(3) " then " (ar (Delta PQR))/(ar (Delta ABC))=?

If Delta ABC ~ Delta PQR with (BC)/(QR) = 1/3 , then find (ar Delta PRQ)/(ar Delta BCA) ?

It is given that Delta ABC - Delta PQR , with (BC)/(QR) = (1)/(4) . Then (ar Delta PQR)/(ar Delta ABC) is equal to:

If triangle ABC - triangle PQR and (BC)/(QR) = 1/4 then (ar(trianglePQR))/(ar(triangleABC)) =

If in two triangles ABC and PQR, (AB)/(QR)=(BC)/(PR)=(CA)/(PQ) , then

In Delta ABC and Delta DEF , we have (AB)/(DE)=(BC)/(EF)=(AC)/(DF)=5/7 , then ar (Delta ABC) : ar (Delta DFR) =?

If Delta ABC ~ Delta PQR , then find /_ B .

triangle ABC ~ triangle PQR , AB : PQ = 3 : 4 then area triangle ABC : area triangle PQR