Bond energies of `N -= N` H-H, `N - H` are respectively `x_1 , x_2, x` and X_3 `kJ mol^(-1)` . Hence, `DeltaH_(f)^(@)(NH_3)` is:

The bond energies (in kJ mol^(-1) ) of P-H, as-H and N-H are respectively.

Enthalpy of formation of NH_(3) is -X kJ and Delta H_(H-H) , Delta H_(N-H) are respectively Y kJ mol^(-1) and Z kj mol^(-1) . The value of Delta H_(N = N) is

Enthalpy of formation of NH_(3) is -X kJ and Delta H_(H-H) , Delta H_(N-H) are respectively Y kJ mol^(-1) and Z kj mol^(-1) . The value of Delta H_(N = N) is

If bond enthalpies Of N-=N,H-Hand N-H bonds are x_(1),x_(2)and x_(3) respectively , DeltaH_(f)^(@) for NH_(3) will be :

Enthalpy of formation of 2mol of NH_(3)(g) is -90KJ , and DeltaH_(H-H) and DeltaH_(N-H) respectively 435KJ mol^(-1) and 390KJ mol^(-1) . The valule of DeltaH_(N-=N) is

Bond energies of H-H and Cl-Cl are "430 kJ mol"^(-1) and "242 kJ mol"^(-1) respectively. DeltaH_(f) for HCl is "91 kJ mol"^(-1) . What will be the bond energy of H-Cl ?

Bond energies of H-H and Cl-Cl are "430 kJ mol"^(-1) and "242 kJ mol"^(-1) respectively. DeltaH_(f) for HCl is "91 kJ mol"^(-1) . What will be the bond energy of H-Cl ?