The amount of energy released when 20 ml of 0.5 M NaOH are mixed with 100 ml of 0.1 M HCl is x kJ. The heat of neutralization (in kJ `"mol"^(-1)`) is:

The amount of heat released, when 20 ml of 0.5 M NaOH is mixed with 100 mL of 0.1M HCl, is x kJ. The heat of neutralisation is

The amount of heat released when 20 ml 0.5 M NaOH is mixed with 100 ml 0.1 M HCl is x kJ .The heat of neutralization is

The amount of the heat released when 20 ml 0.5M NaOH is mixed with 100 mL 0.1 MHClis x kJ. The heat of neutralisation is

The amount of heat released when 20 ml , 0.5 M NaOH is mixed with 100 ml , 0.1 M H_(2)SO_(4) is xKJ . The heat of neutralization will be :-

The amount of heat released when 20 ml , 0.5 M NaOH is mixed with 100 ml , 0.1 M H_(2)SO_(4) is xKJ . The heat of neutralization will be :-

The amount of energy released when 20 mL of 0.5 M NH_4OH are mixed with 100 mL of 0.1 M HCl is x kJ. The heat of dissociation of NH_4OH will be (heat of neutralization of NaOH & HCl is y kJ/mol).