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" 5."2x^(2)-32=0" को हल करो। "...

" 5."2x^(2)-32=0" को हल करो। "

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(i) 2x^(2)-17x+21 =0 (ii) 5y^(2)-32 + 35 = 0

If quad f(x)={4,-3

In ( 5x + 4) a factor of 5x^(3) + 14x^(2) - 32 x - 32

If the equations of the tangent to the circle x^(2)+ y^(2)- 2x + 6y -6 =0 parallel to 3x - 4y + 7=0 is 3x - 4y +k=0 , then the values of k are : a) 5,-35 b) -5,35 c) 7,-32 d) -7,32

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3,""1) and has eccentricity sqrt(2/5) is: (1) 3x^2+""5y^2-32""=""0 (2) 5x^2+""3y^2-48""=""0 (3) 3x^2+""5y^2-15""=""0 (4) 5x^2+""3y^2-32""=""0

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3,""1) and has eccentricity sqrt(2/5) is: (1) 3x^2+""5y^2-32""=""0 (2) 5x^2+""3y^2-48""=""0 (3) 3x^2+""5y^2-15""=""0 (4) 5x^2+""3y^2-32""=""0

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3,""1) and has eccentricity sqrt(2/5) is: (1) 3x^2+""5y^2-32""=""0 (2) 5x^2+""3y^2-48""=""0 (3) 3x^2+""5y^2-15""=""0 (4) 5x^2+""3y^2-32""=""0

Solve each of the following quadratic equations: 2^(2x)-3.2^((x+2))+32=0