[" A force of "(4x^(2)+3x)" N acts on a particle which "],[" displaces it from "x=2m" to "x=3m." The work done "],[" by the force is "]

A force of 3x^(2)-2x+5 acts on a body of mass 5 kg and displaces it from x=0 to x=4 m. What is the work done by the force?

A force vecF=(3x^(2)+2x-7)N acts on a 2 kg body as a result of which the body gets displaced from x=0 to x=5m. The work done by the force will be –

A positon dependent force , F=8-4x+3x^(2)N acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

A positon dependent force , F=8-4x+3x^(2)N acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

A force vecF=(7-2x+3x^(2)) N is applied on a 2 kg mass which displaces it from x = 0 to x = 5 m. Work done in joule is -