For the curve `y=x e^x` , the point

The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

The equation of the normal to the curve y=e^(-2|x| at the point where the curve cuts the line x=-1/2 , is

The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is

The equation of the tangent to the curve y=4e^(-x/4) at the point where the curve crosses Y-axis is equal to

Draw the curve y=e^(x)

Draw the curve y=e^(x)