The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

The acceleration due to gravity near the surface of moon is-

The acceleration due to gravity at the surface of earth (g_(e)) and acceleration due to gravity at the surface of a planet (g_(p)) are equal. The density of the planet is three times than that of earth. The ratio of radius of earth to the radius of planet will be.

" For a given density of planet,the orbital period of a satellite near the surface of the planet of radius "R" is proportional to "R^(N)" .Find the value of "Lambda

The value of acceleration due to gravity 'g' on the surface of a planet with radius double that of the earth and same mean density as that of the earth is ( g_(e) =acceleration due to gravity on the surface of the earth )

The value of acceleration due to gravity .g_p. on the surface of a planet with radius double that of earth and same mean density as that of the earth is ( g_e to acceleration due to gravity on the surface of earth)