`(vecA+2vecB).(2vecA-3vecB)`:-

If veca and vecb are unit vectors such that (veca +vecb). (2veca + 3vecb)xx(3veca - 2vecb)=vec0 then angle between veca and vecb is

If veca and vecb are unit vectors such that (veca +vecb). (2veca + 3vecb)xx(3veca - 2vecb)=vec0 then angle between veca and vecb is

If veca and vecb are unit vectors such that (veca +vecb). (2veca + 3vecb)xx(3veca - 2vecb)=vec0 then angle between veca and vecb is

Given three vectors veca=hati-3hatj,vecb=2hati-thatj and vecc=-2hati+21hatj such that vecalpha=veca+vecb+vecc . Then the resolution of te vector vecalpha into components with respect to veca and vecb is given by (A) 3veca-2vecb (B) 2veca-3vecb (C) 3vecb-2veca (D) none of these

Given three vectors veca=6hati-3hatj,vecb=2hati-6hatj and vecc=-2hati+21hatj such that vecalpha=veca+vecb+vecc . Then the resolution of te vector vecalpha into components with respect to veca and vecb is given by (A) 3veca-2vecb (B) 2veca-3vecb (C) 3vecb-2veca (D) none of these

Given three vectors veca=6hati-3hatj,vecb=2hati-6hatj and vecc=-2hati+21hatj such that vecalpha=veca+vecb+vecc . Then the resolution of te vector vecalpha into components with respect to veca and vecb is given by (A) 3veca-2vecb (B) 2veca-3vecb (C) 3vecb-2veca (D) none of these

|veca pm vecb|^2 = |veca|^2 + |vecb|^2 pm 2|veca||vecb|cos theta and (veca + vecb).(veca - vecb) = |veca|^2 - |vecb|^2

Show that the points having position vectors (veca-2vecb+3vecc),(-2veca+3vecb+2vecc),(-8veca+13vecb) re collinear whatever veca,vecb,vecc may be