The A.M. of a and c is b. If b is also the G.M. of a and c+1 then : `(b-c)^(2)`=

a, b, c are in A.P. If x be the G.M. of a and b, and y be the G.M. of b and c, then prove that b^2 is the A.M. of x_2 and y_2 .

Let a,b,c be in A.P. If p is the A.M. between a and b and q is the A.M between b and c, then b is equal to

a, b, c are in A . P, x is G . M between a and b, y is the G.M between b and c, then b^(2) is

If a is the A.M. between b and c, b the G.M. between a and c, then show that 1/a,1/c,1/b are in A.P.

If a is the A.M. between b and c, b the G.M. between a and c, then show that 1/a,1/c,1/b are in A.P.

If a,b,c are in G.P and A.M of a and b is x and A.M. of b and c is y then…….

a,b,c are in A.P., x is G.M between a and b, y is the G.M between b and c then b^2 is

If x is the A.M. between a and b, y is the A.M. between b and c, while a, b, c are in G.P., then 1/x + 1/y =

If a is the A.M. of b and c and the two geometric means are G_1 and G_2 , then prove that G1^3+G2^3=2a b c