" (iii) "6^(2n+1)-:36=6^(3)

Find the value of n when: ( i ) 5^(2n) xx 5^(3)=5^(9) ( ii ) 8 xx 2^(n+2)=32 ( iii ) 6^(2n+1) div 36=6^(3)

If (6^(n))/(6^(-2))=6^(3) , then n=?

Simplify: (6m-n)(36m^(2)+6mm+n^(2))(3m+2n)^(3)

(-2)x\ (-3)x\ 6\ x\ (-1) is equal to (a)36 (b) -36 (c) 6 (d) -6

(-2)\xx\ (-3)\xx\ 6\ xx\ (-1) is equal to (a)36 (b) -36 (c) 6 (d) -6

(6^(n+3)-32*6^(n+1))/(6^(n+2)-2*6^(n+1))=1

The value of (6^(n+3) - 32.6^(n+1))/(6^(n+2) - 2.6^(n+1)) is equal to

Evaluate: lim_(n rarr oo)((1^(2)+2^(2)+3^(3)+...+n^(2))(1^(3)+2^(3)+3^(3)+...+n^(3)))/(1^(6)+2^(6)+3^(6)+...+n^(6))