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A kite is flying at the height of 75m fr...

A kite is flying at the height of 75m from the ground. The string makes an angle `theta` (where `cot theta` `= 8/15` ) with the level ground. Assuming that there is no slack in the string the new length of the string is equal to :

A

85 metre

B

65 metre

C

75 metre

D

40 metre

Text Solution

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The correct Answer is:
To find the length of the string of the kite flying at a height of 75m with the angle θ such that cot(θ) = 8/15, we can follow these steps: ### Step 1: Understand the relationship between cotangent and the sides of the triangle. The cotangent of an angle in a right triangle is defined as the ratio of the adjacent side (base) to the opposite side (height). Thus, we have: \[ \cot(\theta) = \frac{\text{Base}}{\text{Height}} = \frac{8}{15} \] ### Step 2: Identify the height of the kite. The height of the kite from the ground is given as 75m. Therefore, we can denote: \[ \text{Height} = 75m \] ### Step 3: Set up the equation using cotangent. From the cotangent definition, we can express the base (let's denote it as \( x \)) in terms of the height: \[ \cot(\theta) = \frac{x}{75} = \frac{8}{15} \] ### Step 4: Cross-multiply to solve for the base. Cross-multiplying gives us: \[ 15x = 8 \times 75 \] Calculating \( 8 \times 75 \): \[ 8 \times 75 = 600 \] So, we have: \[ 15x = 600 \] ### Step 5: Solve for \( x \). To find \( x \), divide both sides by 15: \[ x = \frac{600}{15} = 40m \] ### Step 6: Use the Pythagorean theorem to find the length of the string. In a right triangle, the length of the hypotenuse (the string) can be found using the Pythagorean theorem: \[ \text{Hypotenuse}^2 = \text{Base}^2 + \text{Height}^2 \] Substituting the values we have: \[ \text{Hypotenuse}^2 = 40^2 + 75^2 \] Calculating \( 40^2 \) and \( 75^2 \): \[ 40^2 = 1600 \] \[ 75^2 = 5625 \] Adding these together: \[ \text{Hypotenuse}^2 = 1600 + 5625 = 7225 \] ### Step 7: Take the square root to find the length of the string. Now, we take the square root of both sides: \[ \text{Hypotenuse} = \sqrt{7225} = 85m \] ### Conclusion: The length of the string is 85 meters. ---
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