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If sec theta + tan theta = p, (p != 0) t...

If `sec theta + tan theta = p`, `(p != 0)` then `sec theta` is equal to

A

`(p - 1/p),

B

`2 (p - 1/p),

C

`(p + 1/p),

D

`1/2 (p + 1/p),

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given equation: 1. **Given Equation**: \[ \sec \theta + \tan \theta = p \] 2. **Using the Identity**: We know that: \[ \sec^2 \theta - \tan^2 \theta = 1 \] This can be factored as: \[ (\sec \theta + \tan \theta)(\sec \theta - \tan \theta) = 1 \] Since we know that \(\sec \theta + \tan \theta = p\), we can substitute \(p\) into the equation: \[ p(\sec \theta - \tan \theta) = 1 \] 3. **Solving for \(\sec \theta - \tan \theta\)**: Rearranging gives us: \[ \sec \theta - \tan \theta = \frac{1}{p} \] 4. **Setting Up the Equations**: Now we have two equations: - Equation 1: \(\sec \theta + \tan \theta = p\) - Equation 2: \(\sec \theta - \tan \theta = \frac{1}{p}\) 5. **Adding the Two Equations**: Adding Equation 1 and Equation 2: \[ (\sec \theta + \tan \theta) + (\sec \theta - \tan \theta) = p + \frac{1}{p} \] This simplifies to: \[ 2\sec \theta = p + \frac{1}{p} \] 6. **Solving for \(\sec \theta\)**: Dividing both sides by 2 gives us: \[ \sec \theta = \frac{p + \frac{1}{p}}{2} \] 7. **Final Result**: Therefore, the value of \(\sec \theta\) is: \[ \sec \theta = \frac{p + \frac{1}{p}}{2} \]
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