A ball is projected from the origin. The x- and y-coordinates of its displacement are given by `x = 3t and y = 4t - 5t^2`. Find the velocity of projection `("in" ms^(-1))`.

A ball is projected from origin at time t= 0. The x and y coordinates of its displacement are given by (x = 4t^2) and y = (3t - 5) . Then its instantaneous velocity at any time t is

A ball is projected from origin at time t= 0. The x and A y coordinates of its displacement are given by (x = 4t^2) and y = (3t - 5). Then its instantaneous velocity at any time t is

The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x=6t and y=7t-5t^(2) . What is the velocity of projection?

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t^(2) - 5t^(2))m . The velocity with which the projectile is projected is

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t - 5t^(2))m . The velocity with which the projectile is projected is