The frequency of the first overtons of a closed pipe of
length `l_(1)` is equal to that of the first overtone of an
open pipe of length `l_(2)` The ratio of their lengths `(l_(1) : l_(2)` is

The frequency of the first overtone of a closed pipe of length l_(1) is equal to that of the first overtone of an open pipe of length l_(2) . The ratio of their lengths (l_(1):l_(2) is

The frequency of the third overtone of a closed pipe of length L_(c) is the same as the frequency of the sixth overtone of an open pipe of the length L_(o). Then

The frequency of the third overtone of a closed pipe of length Lc is the same as the frequency of the sixth overtone of an open pipe of the length L_o. Then:

The frequency of the first overtone of a closed organ pipe is the same as that of the first overtone of an open pipe. What is the ratio between their lengths ?

First overtone frequency of a closed pipe of lengths l_(1) is equl to the 2^(nd) harmonic frequency of an open pipe of lengths l_(2) the ration (l_(1))/(l_(2))

First overtone frequency of a closed pipe of lengths l_(1) is equl to the 2^(nd) harmonic frequency of an open pipe of lengths l_(2) the ration (l_(1))/(l_(2))

If the frequency of the first overtone of a closed organ pipe of length 33 cm is equal to the frequency of the first overtone of an open organ pipe, then the length of the open organ pipe will be