If `8 sin^(2)theta + 10 sin thetacos theta - 3 cos^(2) theta = 0` then `theta =`

cos^(2)theta-sin theta.cos theta-(1)/(2)=0

If sin theta + sin^(2) theta =1 then cos^(4) theta + cos^(8) theta + 2 cos^(6) theta =

sin^(4)theta+sin^(2)thetacos^(2)theta=?

sin^4theta+2sin^2thetacos^2theta=1-cos^4 theta

If f(theta)=|(cos^(2) theta, cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2) theta, cos theta),(sin theta, -cos theta, 0)| then f((pi)/12)=

sin^(6)theta+cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin^(6)theta=cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin 7 theta * sin theta+sin11theta * sin 3theta= A) sin 4 theta * sin 10theta B) cos 4 theta * cos 10 theta C) sin 8 theta * sin 4 theta D) cos 8 theta * cos 14 theta