what is the maximum mass of `Ba_(3)(PO_(4)_(2)` that can be formed from 0.00240 mol of `Ba(NO_(3))_(2)` and 0.131 g of `Na_(3)PO_(4)`?

The maximum number of moles of Ba_(3)(PO_4)_(2) that can be formed if 2 mole BaCl_2 is mixed with 1 mole Na_3PO_(4) is

The maximum number of moles of Ba_(3)(PO_4)_(2) that can be formed if 2 mole BaCl_2 is mixed with 1 mole Na_3PO_(4) is

For the reaction, 2Na_(2)PO_(4(aq))+3Ba(PO_(3))_(2(aq))rarrBa_(3)(PO_(4))_(2_(s))+6NaNO_(3(aq)) Suppose that a solution contaning 32.8 g of Na_(3)PO_(4) and 26.1 g of Ba(NO_(3))_(2) is mixed. How many g of Ba_(3)(PO_(4))_(2) are formed?

What is the valency of PO_(4) in the compound Ca_(3)(PO_(4))_(2)

Statement-1 : 2 moles of BaCl_(2) react with 3 moles of Na_(3)PO_(4) to form 0.66 mole of Ba_(3)(PO_(4))_(2) Statement-2 : BaCl_(2) is the limiting reactant and some Na_(3)PO_(4) remains unreacted.