ABCD is a square whose side is a. Taking AB and AD as axes, find the equation of the circle circumscribing the square.

ABCD is a square in first quadrant whose side is a,taking AB and AD as axes,prove that the equation to the circle circumscribing the square is x^(2)+y^(2)=a(x+y)

ABCD is a square in first quadrant whose side is a, taking AB and AD as axes, prove that the equation to the circle circumscribing the square is x^2+ y^2= a(x + y) .

ABCD is a square, the length oh whose side is a. taking AB and AD as coordinates axes, the equation of the circle passing through the vertices of the square is

ABCD is a square with side a. If AB and AD are taken as coordiate axes. Then the equation of the circle circumseribing the square is.

ABCD is a square 2a unit. Taking AB and AD as axes of coordinates, the equation to the circle which touches the sides of the square is

ABCD is a square, the length of whose side is a. Taking AB and AD as the coordinate axes, the equation of the circel passing through the ceteices of the square is

ABCD is a square, the length of whose side is a. Taking AB and AD as the coordinate axes, the equation of the circel passing through the ceteices of the square is

ABCD is a square with side a. If AB and AD are taken as positive coordinate axes then equation of circle circumscribing the square is

ABCD is a square with side a. If AB and AD are taken as positive coordinate axes then equation of circle circumscribing the square is