How many moles of electrons are needed for the reduction of `20mL` of `0.5M` solution of `KMnO_(4)` in acid mediumgt

" The number of moles of electrons are needed for the reduction of "20ml" of "0.5M" solution of \(KMnO_{4}\)" in acidic medium is \(x \times10^{-2}mole^{-}\)" .What is "x

How many moles of electron needed in Faraday for reduction of 5 moles of MnO_4^- (in acidic medium)

How many moles and how many grams of HCI are present in 250 ml of 0.5 M HCl solution?

How many moles and how many grams of HCI are present in 250 ml of 0.5 M HCl solution?

How many moles of KMnO_(4) are needed to oxidise a mixture of 1 mole of each FeSO_(4) & FeC_(2)O_(4) in acidic medium :

How many moles of KMnO_(4) are needed to oxidise a mixture of 1 mole of each FeSO_(4) & FeC_(2)O_(4) in acidic medium :

How many moles of KMnO_(4) are needed to oxidise a mixture of 1 mole of each FeSO_(4) & FeC_(2)O_(4) in acidic medium :

How many electrons are involved in reduction of KMnO_4 in basic reduction?