" (ii) "4e^(3x)+1

Find the following integral: int (4e^(3x) + 1) dx

int (2e ^ (5x) + e ^ (4x) -4e ^ (3x) + 4e ^ (2x) + 2e ^ (x)) / (e ((2x) +4) (e ^ (2x) - 1) ^ (2)) dx

Integrate the following with respect to x. (i) e^(3x) " " (ii) e^(5 - 4x) " " (iii) 1/((3x - 2)) " " (iv) 1/((5 - 4x)) .

int (4e^(3x) +1)dx

int (4e^(3x) +1)dx

int (4e^(3x) + 1) dx

[" The solution of equation "],[log((dy)/(dx))=9x-6y+6;" given that "],[y(0)=1" is "],[[" (1) "4e^(6y)=3e^(9x+6)+e^(6)," ( ) "],[" (2) "3e^(6y)=4e^(9x+6)-e^(6)," 3e "6y=2e^(9x+6)+e^(6)],[" (4) "2e^(6y)=3e^(9x+6)-e^(6)]]

sin 2x- 4e^(3x)