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2x+3y=0 3x+4y=5...

`2x+3y=0` `3x+4y=5`

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2x + 3y = 0 , 3 x + 4y = 5 .

Find the equation of the circle whose centre is the point of intersection of the lines 2x-3y+4=0and3x+4y-5=0 and passes through the origin.

Find the equation of the circle whose centre is the point of intersection of the lines 2x-3y+4=0and3x+4y-5=0 and passes through the origin.

Find the equation of the circle whose centre is the point of intersection of the lines 2x-3y+4=0and3x+4y-5=0 and passes through the origin.

Let (2,3) be the focus of a parabola and x + y = 0 and x-y= 0 be its two tangents. Then equation of its directrix will be (a) 2x - 3y = 0 (b) 3x +4y = 0 (c) x +y = 5 (d) 12x -5y +1 = 0

The distance of the point of intersection of the lines 2x-3y+5=0 and 3x+4y=0 from the line 5x-2y=0 is