A particle is executing S.H.M. along 4 cm long line with time period `(2pi)/(sqrt2)` sec. If the numerical value of its velocity and acceleration is same, then displacement will be

A particle is executing S.H.M. from mean position at 5 cm distance, acceleration is 20 cm//sec^(2) then value of angular velocity will be

A particle is executing S.H.M. from mean position at 5 cm distance, acceleration is 20 cm//sec^(2) then value of angular velocity will be

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle executes SHM along a straight line 4cm long. When the displacement is 1cm its velocity and acceleration are numerically equal. The time period of SHM is

Tabulate the values of displacement, velocity and aceleration of particle executing S.H.M.

The particle is executing S.H.M. on a line 6 cms long. If its velocity at mean position is 12 cm/sec, its frequency in Hertz will be:

particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds , then the maximum velocity of the particle will be

The maximum displacement of a particle executing a linear S.H.M. is 5 cm and its periodic time is 2 sec. If it starts from the mean position then the equation of its displacement is given by