A square loop of side 'a' with a capacitor of capacitance C is located between two current carrying long parallel wires as shown. The value of I in the wires in given as `I=(I_0) sin omega t`.

(a) Calculate maximum current in the square loop.
(b) Draw a graph between charges on the upper plates of the capacitor vs time.

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite

A rectangular loop is placed to the left of large current carrying straight wire as shown in Figure. Current varies with time as I=2t . Find direction of induced current I_("in") in the square loop.

A rectangular loop is placed to the left of large current carrying straight wire as shown in Figure. Current varies with time as I=2t . Find direction of induced current I_("in") in the square loop.

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite. The instantaneous current in the circuit will be

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite Total magnetic flux in this loop is

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite Total magnetic flux in this loop is

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite Magnitude of emf in this circuit only due to flux change associated with two long straight current carrying wires will be

In fig, a square loop consistaing of an inductor of inductance L and resistor of resistance R is placed between two long parallel wires. The two long straight wires have time - varing current of magnitude I=(I_0) cos omega t but the direction of current in them are opposite Magnitude of emf in this circuit only due to flux change associated with two long straight current carrying wires will be

A square loop of side length d has a capacitor of capacitance C and the resistance of the loop is R. In the plane of the loop there is a long straight current carrying wire having current I. The distance of the straight wire from the loop is d as shown in figure. The current in the straight wire is made to grow with time as I = alpha t where alpha = 2 As^(-1) . Neglect self inductance of the loop. (a) Find the charge on the capacitor as a function of time (t). (b) Find the heat generated in the loop as a function of time. (c) Who supplies energy for heat dissipation?