In an interference experiment,the ratio of the intensities of the bright and dark fringes is 16 .The ratio of the amplitudes due to the two slits is

In Young's experiment the ratio between the intensities of bright and dark fringes is 9:1 this means

The ratio of the intensities of two waves is 16:9 . The ratio of their amplitudes is

In the Young's double slit experiment, the ratio of intensities of bright and dark fringes is 9. this means that

In young double slit experiment the ratio of intentsities of bright and dark bands is 16 which means

In Young's double-slit experiment, the ratio of intensities of a bright band and a dark band is 16:1 . The ratio of amplitudes of interfering waves will be

In Young's double slit interference experiment, using two coherent waves of different amplitudes, the intensities ratio between bright and dark fringes is 3 Then, the value of the wave amplitudes ratio that arrive there is

In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is 9:1 the ratio of amplitudes of coherent sources is

In YDSE, what is the ratio of fringe width for bright and dark fringes ?

In Young's double slit experiment the ratio of intensities at the position of maxima and minima is 9/1. the ratio of amplitudes of light waves is