[" pH of "0.5M" solution of sodium nitrite in water."(K_(a)" of "HNO_(2)-7times10^(-4))" (Assume "1],[-a-1)]

The hydrolysis constang of 0.1M aqueous solution of sodium acetate if K_(a) of CH_(3)COOH = 1.8 xx 10^(-5) is

The pH of 0.5 M aqueous solution of HF (K_(a)=2xx10^(-4)) is

Calculate the pH of 0.10 M solution of Nh_(4)Cl. The dissociation constant (K_(b)) of NH_(3) is 1.8xx10^(-5)

What is pH of 0.02 M solution of ammonium chloride at 25^(@) C ? K_(b) (NH_(3)) = 1.8 xx 10^(-5) .

Calculate the pH of 0.01M solution of AICI_(3), (K_(a) of [AI(H_(2)O)_(6)]^(3+) is 1.4xx10^(-5))

The pH of a 0.1M solution of NH_(4)Oh (having dissociation constant K_(b) = 1.0 xx 10^(-5)) is equal to

a. Calculate the percentage hydrolysis of 0.003M aqueous solution of NaOH. K_(a) for HOCN = 3.3 xx 10^(-4) . b. What is the pH and [overset(Theta)OH] of 0.02M aqueous solution of sodium butyrate. (K_(a) = 2.0 xx 10^(-5)) .