An aqueous solution at `-2.55^(@)C`. What is its boiling point `(K_(b)^(H_(2)O)=0.52 K m^(-1)`,`K_(f)^(H_(2)O)=1.86 K m^(-1)`?

An aqueous solution at freezes at -2.55^(@)C . What is its boiling point (K_(b)^(H_(2)O)=0.52 K m^(-1) , K_(f)^(H_(2)O)=1.86 K m^(-1) ?

An aqueous solution of NaCI freezes at -0.186^(@)C . Given that K_(b(H_(2)O)) = 0.512K kg mol^(-1) and K_(f(H_(2)O)) = 1.86K kg mol^(-1) , the elevation in boiling point of this solution is:

An aqueous solution of NaCI freezes at -0.186^(@)C . Given that K_(b(H_(2)O)) = 0.512K kg mol^(-1) and K_(f(H_(2)O)) = 1.86K kg mol^(-1) , the elevation in boiling point of this solution is:

An aqueous solution of NaCI freezes at -0.186^(@)C . Given that K_(b(H_(2)O)) = 0.512K kg mol^(-1) and K_(f(H_(2)O)) = 1.86K kg mol^(-1) , the elevation in boiling point of this solution is:

Elevation in boiling point of an aqueous solution of a non-electroluyte solute is 2.01^(@) . What is the depression in freezing point of the solution ? K_(b)(H_(2)O)=0.52^(@)mol^(-1)kg K_(f)(H_(2)O)=1.86^(@)mol^(-1)kg

What is the apparent molecular mass of a weak acid HA (molecular mass= 30 g // mole) in an aqueous solution, which shows elevation in boiling point by 0.0156^(@) C. Given : K_(a)(HA)=10^(-2),K_(b)(H_(2)O)=0.52 K kg mol^(-1)

The boiling point of an aqueous solution is 100.18 .^(@)C . Find the freezing point of the solution . (Given : K_(b) = 0.52 K kg mol^(-1) ,K_(f) = 1.86 K kg mol^(-1))