A normal to the hyperbola, `4x^2_9y^2 = 36` meets the co-ordinate axes `x` and `y` at `A` and `B.` respectively. If the parallelogram `OABP (O` being the origin) is formed, then the locus of `P` is :-

The foci of the hyperbola 4x^2-9y^2=36 is

For the hyperbola 4x^2-9y^2=36 , find the Foci.

If the tangent drawn to the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 at any point P meets the coordinate axes at the points A and B respectively. If the rectangle OACB (O being the origin) is completed, where C lies on (x^2)/(a^2)-(y^2)/(b^2)=lambda . Then, the value of lambda is:

Tangents at any point on the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 cut the axes at A and B respectively,If the rectangle at OAPB (where O is origin) is completed then locus of point P is given by