A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is 200 N, the acceleration of child is `(g=10 m//s^(2))`

A child weighing 25 kg slides down a rope hanging from the branch of a tall tree. If the force of friction acting against him is 2 N , what is the acceleration of the child

A boy of weight 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy's acceleration is (g= 10 ms^(-2) )

A boy of weight 25kg slides down a rope hanging from the branch of a tree. If the force of friction against him is 50N, the boy's acceleration is (g= 10 ms^(-2) )

A fireman of mass 60 kg slides down a pole. As shown in figure. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5. With wht acceleration will the fireman slide down (g=10 m//s^(2))

A fireman of mass 60 kg slides down a pole. As shown in figure. He is pressing the pole with a force of 600 N. The coefficient of friction between the hands and the pole is 0.5. With wht acceleration will the fireman slide down (g=10 m//s^(2))

A boy weighing 250 N slides down upto the ground from the top of a slide. The friction offered by the slide is three tenth of his weight. The length and height of the slide is 10 m and 8 m, respectively. The work done by the slide on the boy as he comes down to the ground is