The area bounded by `f(x)=sin^2x` and the x - axis from x = a to x = b , where `f''(a)=f''(b)=0(AAa,b,in(0,pi))` is

If area bounded by f(x)=sin(x^(2)) with x axis,from x=0 to x=sqrt((pi)/(2)) is A,then

[" The area bounded by the curve "],[y=sin^(-1)(sin x)" and the "x" -axis "],[" from "x=0" to "x=4 pi" is equal to "],[" the area bounded by the curve "],[y=cos^(-1)(cos x)" and the x-axis "],[" from "x=-pi" to "x=" a then the "],[" value of "[a]=[.]" G.I.F "]

Calculate the area bounded by the curve: f (x)= sin ^(2) "" (x)/(2), axis of x and the ordinates: x =0, x = (pi)/(2).

The area bounded by the x-axis the curve y = f(x) and the lines x = a and x = b is equal to sqrt(b^(2) - a^(2)) AA b > a (a is constant). Find one such f(x).

The area bounded by the x-axis the curve y = f(x) and the lines x = a and x = b is equal to sqrt(b^(2) - a^(2)) AA b > a (a is constant). Find one such f(x).

Let f (x) be a continous function such that the area bounded by the curve y =f (x) x-axis and the lines x=0 and x =a is (a ^(2))/( 2) + (a)/(2) sin a+ pi/2 cos a, then f ((pi)/(2)) is

The area bounded by the curves y=f(x) , the x-axis, and the ordinates x=1 and x=b is (b-1)sin(3b+4) . Then f(x) is

Statement 1: The area bounded by parabola y=x^(2)-4x+3 and y=0 is (4)/(3) sq.units. Statement 2: The area bounded by curve y=f(x)>=0 and y=0 between ordinates x=a and x=b (where b>a) is int_(a)^(b)f(x)dx