In a triangle ABC, coordinates of A are (1,2) and the equations of the medians through B and C are `x+y=5 and x=4` respectively. Find the coordinates of B and C.

In a triangle ABC, co-ordinates of A are (1,2) and the equations to the medians through B and C are x+y=5 and x=4 respectively.Then the co-ordinates of B and C will be

in a triangle ABC, if A is (1,2) and the equations of the medians through B and c are x+y=5 and x=4 respectively then B must be:

In a triangle ABC, if A is (1, 2) and the equations of the medians through B and c are x+ y= 5 and x= 4 respectively then B must be:

In a triangle ABC, coordinate of A are (1,2) and the equations of the medians through B and C are respectively, x+y=5&x=4 . Then area of DeltaABC (in sq. units) is:

The centroid of the triangle ABC is at the point (1,2,3) . If the coordinates of A and B are (3,-5,7) and (-1,7,-6) respectively. Find the coordinates of the point C.

The centroid of a triangle ABC is at the point (1,1,1). If the coordinates of A and B are (3,-5,7) and (-1,7,-6) respectively, find the coordinates of the point C.

The centroid of a triangle ABC is at the point (1,1,1). If the coordinates of A and B are (3,-5,7) and (-1,7,-6) respectively,find the coordinates of the point C.

The centroid of a triangle ABC is at the point (1, 1, 1) . If the coordinates of A and B are (3, 5, 7) and (1, 7, 6) , respectively, find the coordinates of the point C.

The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinates of A and B are (3, -5, 7) and (-1, 7, -6), respectively, find the coordinates of the point C.