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siny=xsin(a+y), तब !=...

siny=xsin(a+y), तब `!=`

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If siny=xsin(a+y) , then (dy)/(dx) is :

If siny=xsin(a+y), prove that (dy)/(dx)=(sin^2(a+y))/(sina)

If siny=xsin(a+y), prove that (dy)/(dx)=(sin^2(a+y))/(sina)

If siny=xsin(a+y),\ \ prove that (dy)/(dx)=(sin ^2\ (a+y))/(sina)

If siny=xsin(a+y), prove that (dy)/(dx)=(sin^2(a+y))/(sina)

If siny=xsin(a+y), prove that (dy)/(dx)= (sin^2(a+y))/(sina) .

If siny=xsin(a+y), find x in terms of y and hence find (dx)/(dy)

If siny=xsin(a+y) , then prove that (dy)/(dx)=(sin^(2)(a+y))/sina, a ne npi .

If siny=xsin(a+y) , then (dy)/(dx) is (a) (sina)/(sina sin^2(a+y)) (b) (sin^2(a+y))/(sina) (c) sina sin^2(a+y) (d) (sin^2(a-y))/(sina)