For a binomial distribution `B(n, p), np = 4` and varience npq = 4/3. What is the probability `P (x ge 5)` equal to ?

In a Binomial distribution mean is 4 and variance is 3 find P(X ge 1) .

For a binomial distribution,n=5.If P(X=4)=P(X=3) then p=…….

For a binomial distribution,n=5.If P(X=4)=P(X=3) then p=…….

If X follow a binomial distribution with mean 4 and variance 2 find P(X ge 5)

In a binomial distribution B( n , p =1/4) , if the probability of at least one success is greater than or equal to 9/10 , then n is greater than :

If X follows a binomial distribution with mean 4 and variance 2, find P(X ge5)

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than

In a binomial distribution B(n , p=1/4) , if the probability of at least one success is greater than or equal to 9/(10) , then n is greater than