Let a force ` vecF ` be acting on a body free to rotate about a point O and let ` vecr ` the position vector of any point P on the line of action of the force then torque `( tau )` of this force about point O is defined as ` vectau = vecr xx vecF ` given ` vecF = ( 2 hati + 3hatj - hatk )`N and ` vecr =( hati - hatj + 6 hatk )` m. find the torque of this force

Explanation

`vectau = vecr xx vecF =|( hati, hatj,hatk),( 1,-1,6),(2,3,-1)|= hati (1-18 ) + hatj ( 12 +1 ) hatk (3 +2)`
` vectau =(-17 hati + 13 hatj +5 hatk ) N-m`