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Two particles A and B are projected ...

Two particles A and B are projected in air .A is thrown horizontally .B is thrown vertically up . What is the separation between them after 1 sec .

Text Solution

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` veca_(AB ) = veca_(A) - veca_(B) =0`
` vecC_(AB) = sqrt( 10^2 +10^2)= 10 sqrt(2) therefore S_(AB) =V_(AB) t=( 10 sqrt(2)) t=10 sqrt(2)`m
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