A body of mass 8kg is moved by a force F =3x N, where x is the distance covered . Initial position is x= 2m and final position is x = 10m . If initialy the body is at rest , find the final speed .

Explanation

`F=ma, F= m. (dv)/(dt)`
` 3x = m. (dv)/(dx).(dx)/(dt) , 3x=8. (dv)/(dt).v , 3x dx = 8v dv `
` 3int_(2)^(10)x dx = 8 int_0^(v) v dv , 3[(x^(2))/(2)]^(10)=8[(v^(2))/(2)]^(v) , 3[100-4]=8v^(2) , v^(2) = (3 xx 96)/(8) =36 , v=6 m//s`