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An object of mass 3 kg is at rest . Now ...

An object of mass 3 kg is at rest . Now a force `F= 6t^(2) hati + 2thatj` is applied on the object . Find the velocity of the object at t =3 sec.

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Impulse `= int_0^(3) F dt = int_0^(3) (6t^(2) hati + 2 t hatj ) dt = [2t^(3) hati + t^(2) hatj]_(0)^(3) = 54 hati + 9 hatj`
Impulse = change in linear momentum
` 54 hati + 9 hatj = m(barv- baru) , 54 hati + 9 hatj = 3(barv - bar0), barv = (18 hati + 3 hatj) m//s `
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AAKASH SERIES-LAWS OF MOTION-PRACTICE EXERCISE
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