In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. Find impulse at t=2sec.

Explanation

`v=(dx)/(dt)=4/2 = 2m//s `
velocity between t=0 sec to t =2 sec = 2 m/s
velocity at 2 sec = 0 m/s
Impulse = change in linear momentum
`=m(V_f - V_i) =0.1(0-2) = -0.2 kg ms^(-1)`