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From two diametrically opposite points A and B on earth, moon is observed. The angle `theta` subtended at the moon by the two directions of observation is `1^@ 54^1`. If radius of earth is` 0.638 xx 10^7` m, find the distance of the moon from the earth.

Text Solution

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Distance between points of observation = Diameter of earth
i.e., b=2r`implies b =2xx0.638xx10^(7)=1.276xx10^(7)`m
Angle subtended at moon `theta1^(@)54. = 1.9^(0)`
`implies theta=1.9xx1.745xx10^(-2)= 3.32xx10^(-2) `rad
Distance of moon ,
`D=(b)/(theta)implies D= (1.276xx10^(7))/(3.32xx10^(-2))= 3.84xx10^(8)` m
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From two diametrically opposite points A and B on earth, moon is observed. The angle theta subtended at the moon by the two directions of observation is 1°54 .. If radius of earth is 0.638 xx 10^(7) m, find the distance of the moon from the earth.

The moon is observed from two diametrically opposite points A and B on Earth. The angle theta subtended at the moon by the two directions of observation is 1^(@)52' . Given the diameter of the Earth to be about 1.276 times 10^(7)m , compute the distance of the moon from the Earth.

Knowledge Check

  • The mass of a planet is 1/25 th of the mass of the earth. The distance between the planet and the earth is 6xx 10^8 m. At what distance from the earth, the gravity becomes zero

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  • The radius and acceleration due to gravity of moon are 1/4 and 1/5 that of earth. The ratio of the mass of earth to mass of moon is

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