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If h is the Planck's constant, m = mass ...

If h is the Planck's constant, m = mass of the electron, e = charge of the electron and `in_(0)` = permittivity of vacuum, then `(h^(2)in_(0))/(me^(2))` has the unit

A

newton

B

joule

C

watt

D

metre

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The correct Answer is:
D
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