Velocity and acceleration of a particle at time t=0 are `vecu =(2hati + 3hatj)m//s` s and `a = (4hati +2hatj) m//s^(2)` respectively. Find the velocity and displacement of particle at t = 2s.

Explanation

Here acceleration `veca=(4hati+2hatj)m//s^(2)` is constant
so, we can apply `vecv= vecu+vec (at) and vecs= uvect+(1)/(2) vec (at)^(2)` substituting the proper values, we get
`vecv=(2hati+3haj)+(2) (4hati+2hatj)=(hati+7hatj) m//s and`
`vecs=(2) (2hati+3hatj)+(1)/(2)(2)^(2)(4hati+2hatj)=(12hatI+10 hatj)`
therefore velocity and displacement of particle at t=2s are `(10 hati+7 hatj) m//s and (12 hati+10 hatj)` m respectively.