find the speed of two objects such that when they move uniformly towards each other ,they get 4.0 meters closer each second and when they move uniformly in the same direactions with origiinal speeds they get 4.0 meters closer each 10 sec .

Explanation

Let their speeds be `v_(1) and v_(2)` and let `v_(1) gt v_(2)`
In first Case
In second Case:
Relative velocity `v_(1)-v_(2)=(4)/(10)=0.4" "....(2)`
Solving eqns. (1) and (2) we get
`v_(1)=2.2 m s^(-1), v_(2) 1.8m s^(-1)`