Home
Class 12
PHYSICS
A bullet fired at an angle of 30^(@) wit...

A bullet fired at an angle of `30^(@)` with the horizontal hits the ground 3.0 km away. By adjusting its angle of projection, can one hope to hit a target 5.0 km away ? Assume the muzzle speed to be fixed, and neglect air resistance.

Text Solution

Verified by Experts

We are given that angle of projection with the horizontal, `theta= 30^(@)`. horizontal range.
As `R=(v_(0)^(2)sin 2 theta)/(g), 3=(v_(0)^(2) sin 60^(@))/(g)= (v_(0)^(2))/(g) xx (sqrt(3))/(2)`
or `(v_(0)^(2))/(g) =2 sqrt(3) km`
Since the muzzle speed `(v_(0))` is fixed.
`R_("max")=(v_(0)^(2))/(g)=2 sqrt(3)=2xx1.732=3.46` km
Obviously, it is not possible to hit the target 5km away.
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-A (Vectors & Scalars)|25 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-A (Addition & Subtractions of Vectors)|10 Videos

  • MAGNETISM

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|13 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

Similar Questions

Explore conceptually related problems

A particle aimed at a target, projected with an angle 15^(0) with the horizontal is short of the target by 10 m. If projected with an angle of 45° is away from the target by 15 m, then the angle of projection to hit the target is

A projectile shot at angles of 45^(@) above the horizontal strikes a buliding 30 m away at a point 15 m above the point of projection. Find : (a) the speed of projection . (b) the magnitude and direction of velocity of projectile when it strikes the building .

A gun fires a bullet at a speed of 140 ms^(-1) . If the bullet is to hit a target at the same level as the gun and at 1km distance, the angle of projection may be