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A golfer standing on the ground hits a b...

A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle `theta` above the horizontal if `tan theta=(5)/(12)` find the time for which the ball is at least 75m above the ground? (`g=10 m//s^(2))`

Text Solution

Verified by Experts

`v_(y)= sqrt(u_(y)^(2)-2gy) `
`=sqrt(52xx52xx(5xx5)/(13xx13)-2xx10xx15)= sqrt(16xx25-300)=10`
`Delta =(2u_(y))/(10)=(2xx10)/(10)=2s`
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