A ball of 200g is at one end of a string of length 20 cm. it is revolved in a horizontal circle at an angular frequency of 6 rpm. Find (i) the angular velocity (ii) the linear velocity, (iii) the centripetal acceleration.

Explanation

(i) The angular velocity,
` omega=(2piN)/(t)=(2pi xx 6)/(60)=(pi)/(5)=0.6284 rad s^(-1)`
(ii) the linear velocity `v= r omega`
`=0.20xx0.6284=0.1257 m s^(-1)`
(iii) The centripetal acceleration `a_(c)=r omega^(2)`
`=0.20 xx (0.6284)^(2)=0.0970 m s^(-2)`