Home
Class 12
PHYSICS
The position vector of a particle isvecr...

The position vector of a particle is`vecr = (a cos omega t)hati + (a sin omegat)hatj`. the velocity of the particle is

A

directed towards the origin

B

directedaway from the origin

C

parallel to the position vector

D

perpendicular to the position vector.

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-A ( Vector & scalar)|2 Videos
  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-A (Resolution, motion in plane and motion of boat|4 Videos
  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-A (Relative velocity)|18 Videos
  • MAGNETISM

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|13 Videos
  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

Similar Questions

Explore conceptually related problems

A particle moves so that its position vectors varies with time as vecr=Acosomegathati+Asinomegathatj . Find the (a)Initial velocity of the particle (b)angle between the position vector and velocity of the particle atony time. ©Speed at any instant .

The position vector of a particle moving in a plane is given by r =a cos omega t hati + b sin omega I hatj, where hati and hatj are the unit vectors along the rectangular axes C and Y : a,b, and omega are constants and t is time. The acceleration of the particle is directed along the vector

A particle moves so that position vector s given by vec(r) = cos omega t hat(x) + sin omega t hat(y) . Where omega is a constant. Which of the following is true ?

The position vector of a particle is given by r = 3t^(2)hati + 4t^(2)hatj + 7hatk m at a given time 't'. The net displacement of the particle after 10s is

The motion of a particle is given by X=Asinomegat+B cos omegat the motion of the particle is