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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where AB = a. They boy at B starts runing in a direction perpendicular to AB with velocity` v_(1)`. The boy at A starts runing simultaneously with velocity v and catches the other in a time t, where t is

A

`(a)/(sqrt(v^(2)+v_(1)^(2)))`

B

`(a)/(v+v_(1))`

C

`(a)/(v-v_(1))`

D

`sqrt((a^(2))/(v^(2)-v_(1)^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D
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