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A body is projected horizontally from a ...

A body is projected horizontally from a height of 78.4 m with a velocity `10 ms^(-1)`. Its velocity after 3 seconds is - `(g = 10 ms^(-2)]` (Take direction of projection on `veci` and vertically upward direction on `vecj)`

A

` 10 hat i - 30 hat j`

B

`10 hat i + 30 hat j`

C

`20 hat - 30 hat j`

D

`10 hat i + 10 sqrt(3) hat j`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A body is projected horizontally from a height of 78.4 m with a velocity 10 ms^(-1) . Its velocity after 3 seconds is [g = 10 ms^(-2) ] (Take direction of projection on veci and vertically upward direction on j)

    A
    `10hati - 30 hatj`
    B
    `10hati + 30 hatj`
    C
    `20hati - 30 hatj`
    D
    `10hati + 10sqrt(3) hatj`

  • A body is projected horizontall from a height of 78.4 m with a velocity 10 ms^(-1) . Its velocity after 3 seconds is - [g = 10 ms^(-2)] (Take direction of projection on vec(i) and vertically upward direction on vec(j) ).

    A
    `10 hat(i) - 30 hat(j)`
    B
    `10 hat(i) + 30 hat(j)`
    C
    `20 hat(i) - 30 hat(j)`
    D
    `10 hat(i) + 10 sqrt(3) hat(j)`

  • A body is projected horizontally from a height of 78.4 m with a velocity 10ms^(-1) . Its velocity after 3 second is : (g=10ms^(-2)) (Take direction of projection on vec(i) and vertically upward direction on vec(i) ).

    A
    `10 hat(i) - 30 hat(j)`
    B
    `10 hat(i) + 30 hat(j)`
    C
    `20 hat(i) - 30 hat(j)`
    D
    `10 hat(i) + 10 sqrt(3) hat(j)`

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