Home
Class 12
PHYSICS
Two particles having position vectors ve...

Two particles having position vectors `vecr_(1)=(3hati+5hatj)mandvecr_(2)=(-5veci+3vecj)m` are moving with velocities `vecV_(1)=(4hati-4hatj)ms^(-1)andvecV_(2)=(aveci-3vecj)ms^(-1)`. If they collide after 2 seconds, the value of 'a' is

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (Relative velocity)|5 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (A boat in a river)|3 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (Lamni.s theorem)|3 Videos

  • MAGNETISM

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|13 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

Similar Questions

Explore conceptually related problems

At a given instant of time two particles are having the position vectors 4 hati -4hatj + 7 hatk metre and 2 hat i +2 hatj + 5hatk respectively. If the velocity of the first particle be 0.4 hati ms^-1 , the velocity of second particle in metre per second if they collide after 10 s is

The work done in moving an object from origion to a point whose position vector is vec r= 3hati+2hatj-5hatk by a force vecF= 2hati-hatj-hatk is

Knowledge Check

  • Two particles having position vectors vecr_1 = (3hati + 5hatj)m and vecr_2 = (-5hati + 3hatj)m are moving with velocities vecV_1 = (4hati - 4hatj) ms^(-1) and vecV_2 = (a veci - 3vecj) ms^(-1) . If they collide after 2 seconds, the value of 'a' is

    A
    2
    B
    4
    C
    6
    D
    8

  • Two particles having position vectors vecr_1 = (3hati + 5hatj)m and vecr_2 = (-5hati + 3hatj)m are moving with velocities vecV_1 = (4hati - 4hatj) ms^(-1) and vecV_2 = (a veci - 3vecj) ms^(-1) . If they collide after 2 seconds, the value of 'a' is

    A
    2
    B
    4
    C
    6
    D
    8

  • Two particles having position vectors vec(r_1) = (3veci+5vecj)m and vec(r_2) =(-5veci +3vecj)m are moving with velocities vec(V_1) =(4veci -4vecj)ms^(-1) and vec(V_2) = (aveci – 3vecj)ms^(-1) . If they collide after 2 seconds, the value of 'a' is

    A
    2
    B
    4
    C
    6
    D
    8

    • Similar Questions

    Explore conceptually related problems

    Two particles having position vectors vecr_(1) = (3vec(i) + 5 vec(j))m and vecr_(2) = (-5vec(i) + 3vec(j))m are moving with velocities V_(1) = (4vec(i) - 4vec(j))ms^(-1) and V_(2) = (avec(i) - 3vec(j))ms^(-1) . If they collide after 2 seconds the value of .a. is

    Two particles having position vectors vecr_1=(3hati+5hatj)m and r_2 =(-5hati + 3hatj) m are moving with velocities V_1 = (4hati +3hatj)m/s and V_2 = (-ahati + 4hatj) m/s . If they collide after 2 s, the value of a is

    The resultant of the forces vecF_(1) = 4hati-3hatj and vecF_(2) = 6hati + 8hatj is

    Two particles of equal mass have velocities vecV_(1) = 4veci and vecV_(2) = 4vecj ms^(-1) . First particle has an acceleration veca_(1) = (5veci + 5vecj) ms^(-2) while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

    Two particles of equal mass have velocities vecV _(1)= 4hati ms^(-1) and vecV _(2)= 4hatj ms^(-1) First particle has an acceleration veca_(1)=(5hati+5hathatj)ms^(-1) while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of

    Home
    Profile