Home
Class 12
PHYSICS
A particle moves in a circular path suc...

A particle moves in a circular path such that its speed v varies with distance as `v=alphasqrts` where `alpha` is a positive constant. Find the acceleration of particle after traversing a distance S?

A

`alpha^(2)sqrt((1)/(4)-(S^(2))/(R^(2)))`

B

`alpha^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))`

C

`alphasqrt((1)/(2)+(S^(2))/(R^(2)))`

D

`alpha^(2)sqrt((1)/(2)+(S^(2))/(R^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise EXERCISE-3 (Oblique projection )|25 Videos

  • MAGNETISM

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|13 Videos

  • MOTION IN A PLANE

    AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

Similar Questions

Explore conceptually related problems

A particle moves in a circular path such that its speed v varies with distance as V= alphasqrt(s) where alpha is a positive constant. Find the acceleration of the particle after traversing a distance s.

A particle of mass m kg moves along the X-axis with its velocity varying with the distance travelled as v= kx^(beta) , where k is a positive constant. The total work done by all the forces during displacement of the particle for x = 0 to x=d is close to

A particle moves in a circle with speed v varying with time as v(t) = 2t. The total acceleration of the particle after it completes 2 rounds of cycle is